PyPI: pyftpdlib
CVE-2007-6738
Safety vulnerability ID: SFTY-20101019-44301
Safety legacy ID: pyup.io-53972
pyftpdlib before 0.1.1 does not choose a random value for the port associated with the PASV command, which makes it easier for remote attackers to obtain potentially sensitive information about the number of in-progress data connections by reading the response to this command.
Overview
pyftpdlib Use of Insufficiently Random Values of port selection on PASV command
Advisory
pyftpdlib before 0.1.1 does not choose a random value for the port associated with the PASV command, which makes it easier for remote attackers to obtain potentially sensitive information about the number of in-progress data connections by reading the response to this command.
How to Fix
Mitigation and Workarounds
---
Vulnerable Functions
Functions linked to known vulnerabilities.
References
- https://getsafety.com/vulnerabilities/SFTY-20101019-44301/CVE-2007-6738
- https://nvd.nist.gov/vuln/detail/CVE-2007-6738
- http://code.google.com/p/pyftpdlib/source/browse/trunk/HISTORY
- https://github.com/giampaolo/pyftpdlib/commit/d171bdc4ef7ac769671946a8a3e5eaafc39a9202
- https://github.com/pypa/advisory-database/tree/main/vulns/pyftpdlib/PYSEC-2010-22.yaml
- https://github.com/advisories/GHSA-gh7c-cg3x-pmcr
Verified by Safety
Our Cybersecurity Intelligence Team reviewed this vulnerability. We combine public data with our own research to find issues not yet reported to public sources.
Learn more